Northern East stats & predictions

Influence of Weather Conditions

The weather can significantly impact how football matches unfold, especially in Northern East England where conditions can be unpredictable. Here’s how it might affect tomorrow’s games:

• Pitch Conditions:: Rain can lead to slower pitches, affecting passing accuracy and increasing ball handling errors.
  • Tactical Adjustment:: Teams might focus more on ground passes rather than long balls or crosses in wet conditions.
• Airborne Play:: Windy conditions could influence set-pieces like corners and free-kicks.
  • Tactical Adjustment:: Teams may aim for more direct play during windy periods or use set-pieces strategically to exploit gusts of wind.
• Cold Temperatures:: Colder weather may affect player stamina and speed.
  • Tactical Adjustment:: Managers might rotate players more frequently or employ a more conservative approach early in the game to conserve energy.

Potential Impact of Key Player Absences

Injuries and suspensions can drastically alter team dynamics and strategies. Here are some key player absences that could influence tomorrow’s matches:

• Team A’s Defender Out with Injury:: The absence of a key defender might weaken their backline against an attacking team like Team B.
  • Tactical Adjustment:: They may adopt a deeper defensive line or deploy an additional midfielder for added protection.
• Suspension of Team D’s Playmaker:: Losing a creative force can hinder their ability to break down defenses.
  • Tactical Adjustment:: They might rely more heavily on wing play or direct attacks from set-pieces to compensate for the loss.
  syzc/algorithm<|file_sep|>/leetcode/8.String_to_Integer_atoi.py class Solution(object): def myAtoi(self,s): """ :type s: str :rtype: int """ s = s.strip() if len(s) ==0: return if s[0] == '+' or s[0] == '-': sign = s[0] s = s[1:] else: sign = '+' if len(s) ==0: return res = '' for c in s: if c >= '0' and c <= '9': res += c else: break if res == '': return res = int(res) if sign == '-': res = -res res = min(max(-2**31,res),2**31-1) return res if __name__ == '__main__': print(Solution().myAtoi('4193 with words')) print(Solution().myAtoi('words and 987')) print(Solution().myAtoi('-91283472332')) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/14.Longest_Common_Prefix.py class Solution(object): def longestCommonPrefix(self,strs): if len(strs) ==0: return '' minlen = min([len(s) for s in strs]) for i in range(minlen): for j in range(len(strs)-1): if strs[j][i] != strs[j+1][i]: return strs[j][:i] return strs[0][:minlen] if __name__ == '__main__': print(Solution().longestCommonPrefix(['a','aa','aaa'])) print(Solution().longestCommonPrefix(['aa','a'])) print(Solution().longestCommonPrefix(['abab','abac'])) print(Solution().longestCommonPrefix(['abc','abcd'])) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/18_4sum.py class Solution(object): def fourSum(self,num,target): num.sort() result = [] for i in range(len(num)-3): if i >0 and num[i] == num[i-1]: continue for j in range(i+1,len(num)-2): if j > i+1 and num[j] == num[j-1]: continue start,end = j+1,len(num)-1 while start target: end-=1 else: start+=1 if __name__ == '__main__': print(Solution().fourSum([1,-2,-5,-4,-3,3,3,5],-11)) print(Solution().fourSum([0,-2,-5,-4,-3,3],-6)) print(Solution().fourSum([2,-5,-2,-5,-2,-3,8],-7)) <|file_sep|># Definition for singly-linked list. class ListNode(object): def __init__(self,x): self.val = x self.next = None class Solution(object): def reverseKGroup(self,listNode,k): prehead = ListNode(0) if __name__ == '__main__': lstnode = ListNode(10) lstnode.next = ListNode(20) lstnode.next.next = ListNode(30) lstnode.next.next.next = ListNode(40) lstnode.next.next.next.next = ListNode(50) Solution().reverseKGroup(lstnode,3) <|file_sep|># Definition for singly-linked list. class ListNode(object): def __init__(self,x): self.val = x self.next = None class Solution(object): def swapPairs(self,listNode): prehead = ListNode(0) if __name__ == '__main__': lstnode = ListNode(10) lstnode.next = ListNode(20) lstnode.next.next = ListNode(30) lstnode.next.next.next = ListNode(40) lstnode.next.next.next.next = ListNode(50) Solution().swapPairs(lstnode) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/33.Search_in_Rotated_Sorted_Array.py class Solution(object): def search(self,num,target): if __name__ == '__main__': print(Solution().search([5],5)) print(Solution().search([7],8)) print(Solution().search([7],6)) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/26.Remove_Duplicates_from_Sorted_Array.py class Solution(object): def removeDuplicates(self,arr): if __name__ == '__main__': arr=[0] print(Solution().removeDuplicates(arr),arr) arr=[0,0] print(Solution().removeDuplicates(arr),arr) arr=[0,0,1] print(Solution().removeDuplicates(arr),arr) arr=[0]*10000+list(range(10000)) print(Solution().removeDuplicates(arr),arr) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/20_Valid_Parentheses.py class Solution(object): def isValid(self,s): if __name__ == '__main__': s='()' print(Solution().isValid(s)) s='()[]{}' print(Solution().isValid(s)) s='((()))' print(Solution().isValid(s)) s='((())' print(Solution().isValid(s)) s='([]{})' print(Solution().isValid(s)) s='([]{})(' print(Solution().isValid(s)) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/13_Roman_to_Integer.py class Solution(object): def romanToInt(self,s): if __name__ == '__main__': s='III' print(Solution().romanToInt(s)) s='IV' print(Solution().romanToInt(s)) s='IX' print(Solution().romanToInt(s)) s='LVIII' print(Solution().romanToInt(s)) s='MCMXCIV' print(Solution().romanToInt(s)) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/24_Swap_Nodes_in_Pairs.py # Definition for singly-linked list. class ListNode(object): def __init__(self,x): class Solution(object): def swapPairs(self,listNode): if __name__ == '__main__': lstNode=ListNode(10) lstNode.next=ListNode(20) lstNode.next.next=ListNode(30) lstNode.next.next.next=ListNode(40) Solution.swapPairs(lstNode) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/23_Merge_k_Sorted_Lists.py # Definition for singly-linked list. class ListNode(object): def __init__(self,x): class Solution(object): def mergeKLists(self,lsts): if __name__=='__main__': listNode1=ListNode(-10) listNode1.next=ListNode(-8) listNode2=ListNode(-9) listNode2.next=ListNode(-7) listNode3=ListNode(-11) Solution.mergeKLists([listNode1,listNode2,listNode3]) <|file_sep|># Definition for singly-linked list. class ListNode(object): def __init__(self,x): self.val = x self.next = None class Solution(object): def reverseBetween(self,listNode,m,n): if __name__ == '__main__': lstnode=ListNode(10) lstnode.next=ListNode(20) lstnode.next.next=ListNode(30) Solution.reverseBetween(lstnode,m,n) <|repo_name|>syzc/algorithm<|file_sep|>/leetcode/7.Reverse_Integer.py class Solution(object): def reverse(self,num): if __name__=='__main__': num=-123 Solution.reverse(num) <|file_sep|># Definition for singly-linked list. class ListNode(object): def __init__(self,x): self.val=x self.next=None class Solution(object): def mergeTwoLists(l1,l2): def mergeKLists(lists): if __name__=='__main__': listNode1=ListNode(-10); listNode1.listNode(ListNode(-8)); listNode2=ListNode(-9); listNode2.listNode(ListNode(-7)); listNode3=ListNode(-11); Solutoin.mergeKLists([listNode1,listNode2,listNode3]); e right up until it gets too close to that one pixel; if it were a circle we'd just stop drawing when we got within radius of that pixel. if (center.x + dx >= pixel.x && center.x + dx <= pixel.x + pixel.width && center.y + dy >= pixel.y && center.y + dy <= pixel.y + pixel.height) { break; } } return path